Ld = length of deflecting plates, m d = distance between deflecting plates,m m = mass of the electron ,kg L = distance between screen and the centre of the deflecting plates, m Ea = accelerating voltage to the plates, volts Ed = deflecting potential of the plates (I) Velocity of the electron Soln Velocity of electron, Vox = √{(2eEa)/(m)} Ea = 2500 v Ed = 150v Ld = 1.5cm L = 55cm d = 6 mm m = 9.1094 x 10^-31 kg e = 1.6022 x 10^ -19 Coulombs = {√ (2 x 1.6022 x 10^-19 x 2500)/(9.1094x 10^-31)} = √ 8.794x 10^ 14 = 29655037.64 m/s (II) Amount of deflection D = {((L x Ld x Ed)/(2 x d x Ea)) x (m)} = {((0.55 x 0.015 x 150)/(2 x 6 x 10^-3 x 2500))} = 0.04125 m (III) Deflection sensitivity = { ( Ld x L )/(2 x d x Ea)} = { ( 1.5 x 10^ -2 x 0.55)/(2 x 6 x 10^ -3 x 2500)} = 2.75 x 10^ -4 m/ volt (IV) Deflection factor ...
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